document.write( "Question 1051454: Jack is
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document.write( "4 times as old as Lacy.
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document.write( "10 years ago the sum of their ages was
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document.write( "40. How old are they now? \n" );
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Algebra.Com's Answer #667045 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Jack is 4 times as old as Lacy. J = 4L10 years ago... 10 years ago Jack was J-10\r\n" ); document.write( "10 years ago Lacy was L-10...the sum of their ages was 40. J-10 + L-10 = 40 \r\n" ); document.write( "\r\n" ); document.write( "Simplify that and substitute 4L for J,\r\n" ); document.write( "then solve the equation for L. That will be\r\n" ); document.write( "Lacy's age. Then Substitute what you get for \r\n" ); document.write( "L in J = 4L to find Jack's age.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |