document.write( "Question 1051454: Jack is
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Algebra.Com's Answer #667045 by Edwin McCravy(20056)\"\" \"About 
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\n" ); document.write( "Jack is 4 times as old as Lacy.
J = 4L
10 years ago...
10 years ago Jack was J-10\r\n" );
document.write( "10 years ago Lacy was L-10
...the sum of their ages was 40.
J-10 + L-10 = 40 \r\n" );
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document.write( "Simplify that and substitute 4L for J,\r\n" );
document.write( "then solve the equation for L. That will be\r\n" );
document.write( "Lacy's age. Then Substitute what you get for \r\n" );
document.write( "L in J = 4L to find Jack's age.\r\n" );
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document.write( "Edwin
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