document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91836>Question 91836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If simple interest on $6000 for 3.5 years is $945, find the simple interest on $5000 for 8 months at the same rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66703 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If simple interest on $6000 for 3.5 years is $945, find the simple interest on $5000 for 8 months at the same rate.<BR>\n" );
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document.write( "Figure the rate of the 1st investment.<BR>\n" );
document.write( "I = Prt<BR>\n" );
document.write( "945 = 6000*r*3.5 <BR>\n" );
document.write( "r = 945/[6000*3.5]<BR>\n" );
document.write( "r = 0.045 or 4.5% per year<BR>\n" );
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document.write( "Figure the interest on the 2nd investment:<BR>\n" );
document.write( "I = Prt<BR>\n" );
document.write( "I = 5000*0.045*(2/3)<BR>\n" );
document.write( "I = $150<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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