document.write( "Question 1051519: Ten voters are randomly selected and asked if they will vote for the incumbent President. Five say yes and three say no. Two students are randomly selected with no replacement between selections.
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document.write( "Draw a tree diagram for the two draw and indicate all probabilities
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document.write( "What is probability two students will say yes?
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document.write( "What is the probability that two will say no?
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document.write( "What is the probability that the selection ends up with a one yes and one no?
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document.write( "What is the probability that the second said yes after the first said no?\r
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document.write( "I have multiple problems such as this one and I know that if I had one example I could work off of it would help me understand better the process. I appreciate anything you could help me with. Thank you for your patience. \n" );
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Algebra.Com's Answer #666999 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Yes-----5/8-----yes 4/7 20/56 ANSWER A. \n" ); document.write( "-----------------no 3/7 15/56\r \n" ); document.write( "\n" ); document.write( "No-----3/8-----yes 5/7 15/56 \n" ); document.write( "----------------no 2/7 6/56 ANSWER B. \n" ); document.write( "That adds to 1.0 \n" ); document.write( "C 30/56, adding \n" ); document.write( "D. 15/56.\r \n" ); document.write( "\n" ); document.write( "Once you have the tree, you can read off the probabilities to get the answers to the questions. With no replacement, the denominator must fall by one. The numerator may fall or not depending upon whether it was selected the first time. In all instances, the probabilities for each draw must add to 1. The total probabilities for the draw must also add to 1.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |