document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051522>Question 1051522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Isaiah has 7.15 in dimes and nickels. He has a total of 91 coins<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666997 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=dimes<BR>\n" );
document.write( "y=nickels<BR>\n" );
document.write( "x+y=91; that is a count of the coins.<BR>\n" );
document.write( ".10x+.05y=7.15; this is a count of the money<BR>\n" );
document.write( "multiply the bottom by -20, to make the second term -1 y, because then we can eliminate y<BR>\n" );
document.write( "-2x-y=-143.0<BR>\n" );
document.write( "-x=-52<BR>\n" );
document.write( "y=52 dimes or $5.20<BR>\n" );
document.write( "x=39 nickels or $1.95<BR>\n" );
document.write( "They sum to $7.15. </SPAN>\n" );
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