document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051504>Question 1051504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In any triangle, the sum of the measures of the angles is 180 degrees.  In triangle ABC, angle A s 3 times as large as angle B and also 16 degrees larger than angle C.  FInd the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666985 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 3B divide both sides by 3: B = 1/3A<BR>\n" );
document.write( "A = C+16 Subtract 16 on both sides: C = A-16<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A+1/3A+A-16 = 180<BR>\n" );
document.write( "A+1/3A+A = 196<BR>\n" );
document.write( "3/3A+1/3A+3/3A = 196<BR>\n" );
document.write( "7/3A = 196 multiply both sides times 3<BR>\n" );
document.write( "7A = 588<BR>\n" );
document.write( "A = 84<BR>\n" );
document.write( "B = 84/3 = 28<BR>\n" );
document.write( "C = 84-16 = 68<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "84+28+68 = 180 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );