document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91842>Question 91842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travels from Morena to Nadina in seven hours. On the return trip the speed is increased by 7 mph and the trip takes six hours. How far apart are the towns Morena and Nadina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66697 by </B><A HREF=/tutors/aboutme.mpl?userid=psychopsibilin><B>psychopsibilin(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psychopsibilin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the distance be X miles and the speed of the car on the forward journey be y mph. Hence time taken= x/y hours. On the return journey, the speed is increased by 7 mph, hence new speed is y+7 mph. Hence time taken = x/(y+7) hrs= 6 hrs<BR>\n" );
document.write( " from the 1st eq, we get x=7y: from the second we get x= 6y+42: hence 6y+42=7y<BR>\n" );
document.write( "hence y=42. subsituring the value of y in eq 1, we get x(distance)=294 miles </SPAN>\n" );
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