document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051473>Question 1051473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello I need help with my triangle and how to solve it.. The right-angled triangle in the diagram has sides of length 7x cm, 24x cm and 150cm. (a) Show that x2. = 36. [2]. (b) Calculate the perimeter of the triangle. Answer(b) cm [1]. These are the things I need help with please respond to me and thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666957 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) Using the Pythagorean Theorem<BR>\n" );
document.write( "(7x)^2 + (24x)^2 = 150^2<BR>\n" );
document.write( "49x^2 + 576x^2 = 22500<BR>\n" );
document.write( "625x^2 = 22500<BR>\n" );
document.write( "x^2 = 22500/625<BR>\n" );
document.write( "x^2 = 36cm^2<BR>\n" );
document.write( "|<BR>\n" );
document.write( "b) x = 6cm<BR>\n" );
document.write( "P  = 7*6cm + 34*6cm + 150cm = 396cm </SPAN>\n" );
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