document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051388>Question 1051388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square has an area that measures twice the area of a circle. Calculate the ratio of the perimeter of the square to the circumference of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666906 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let s be the side of the square and r be the radius of the circle, then<BR>\n" );
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document.write( "1) s^2 = 2*pi*r^2<BR>\n" );
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document.write( "Perimeter of square = 4s<BR>\n" );
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document.write( "Circumference of circle = 2*pi*r<BR>\n" );
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document.write( "from equation 1) s = square root (2*pi*r^2)<BR>\n" );
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document.write( "ratio of perimeter of square to circumference of the circle = (4*r*square root(2*pi)) / (2*pi*r) = (2*square root(2*pi)) / pi<BR>\n" );
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document.write( "square the numerator and denominator<BR>\n" );
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document.write( "4 * 2 * pi / pi^2 = 8 / pi<BR>\n" );
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