document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051393>Question 1051393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bismut-214 has a half life of approximately 20 minutes. find the amount of bismuth-214 left from a 30 gram sample after 156 days. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666902 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bismut-214 has a half life of approximately 20 minutes. find the amount of bismuth-214 left from a 30 gram sample after 156 days.<BR>\n" );
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document.write( "156 days = 3744 hours = 11232 20 minute periods.<BR>\n" );
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document.write( "Amount = 30*(1/2)^11232<BR>\n" );
document.write( "< 10^-99 grams<BR>\n" );
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document.write( "Did you mean 156 hours? </SPAN>\n" );
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