document.write( "Question 1051281: Prove that the difference of the squares of two consecutive odd numbers is a multiple of 8. Note that an even number can be written as 2n.
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Algebra.Com's Answer #666822 by richard1234(7193) $\"\"$ $\"About$

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Let the odd numbers be 2n-1 and 2n+1 where n is an integer\r
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\n" ); document.write( "\n" ); document.write( "(2n+1)^2 - (2n-1)^2 = (4n^2 + 4n + 1) - (4n^2 - 4n + 1) = 8n\r
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\n" ); document.write( "\n" ); document.write( "8n is a multiple of 8, so we are done. \n" ); document.write( "

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