document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16216>Question 16216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you work this? Please help!! \r<BR>\n" );
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document.write( "Heres the word problem:\r<BR>\n" );
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document.write( "Adult tickets cost $9 each and student tickets cost $6 each. A total of 29 tickets were sold worth $210. How many adult tickets were sold?\r<BR>\n" );
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document.write( "*Show your work* </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66681 by </B><A HREF=/tutors/aboutme.mpl?userid=mathispowerful><B>mathispowerful(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathispowerful><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem can be solved by a 2x2 system of equations.\r<BR>\n" );
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document.write( "Let A to represent adults<BR>\n" );
document.write( "    S to represent students\r<BR>\n" );
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document.write( "then A + S = 29<BR>\n" );
document.write( "    9A + 6S = 210\r<BR>\n" );
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document.write( "solve it: multiply the first equation by 6: <BR>\n" );
document.write( "we have 6A + 6S = 174<BR>\n" );
document.write( "        9A + 6S = 210\r<BR>\n" );
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document.write( "do subtraction(second one minus first one): 3A = 36\r<BR>\n" );
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document.write( "A = 12\r<BR>\n" );
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document.write( "so 12 adult tickets were sold. </SPAN>\n" );
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