document.write( "Question 1051097: Find the inverse of the following function:
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Algebra.Com's Answer #666692 by Boreal(15235)\"\" \"About 
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(2x+1)/(3x-2)=y
\n" ); document.write( "change x and y
\n" ); document.write( "x=(2y+1)/(3y-2)
\n" ); document.write( "multiply through by 3y-2
\n" ); document.write( "3xy-2x=2y+1
\n" ); document.write( "3xy-2y=2x+1
\n" ); document.write( "y(3x-2)=2x+1
\n" ); document.write( "y=(2x+1)/(3x-2)
\n" ); document.write( "The function is the same as its inverse. This happens when the function is symmetrical over a line y=x and is called an involution.
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