document.write( "Question 1051026: Could someone please help with this?:\r
\n" ); document.write( "\n" ); document.write( "The SAT math scores for all seniors in a high school are normally distributed with population standard deviation of 200. 100 seniors from the school are randomly selected, and their SAT math scores has a sample mean of 650.\r
\n" ); document.write( "\n" ); document.write( "(a) What distribution will you use to determine the critical value for a confidence interval estimate of the mean SAT math score for the seniors in the high school? Why?\r
\n" ); document.write( "\n" ); document.write( "(b) Construct a 95% confidence interval estimate of the mean SAT math score for the seniors in the high school. (Show work and round the answer to two decimal places)\r
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\n" ); document.write( "\n" ); document.write( "(c) Is a 90% confidence interval estimate of the mean SAT math score wider than the 95% confidence interval estimate you got from part (b)? Why? [You don’t have to construct the 90% confidence interval]\r
\n" ); document.write( "\n" ); document.write( "Thank you for any help!
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Algebra.Com's Answer #666645 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
The SAT math scores for all seniors in a high school are normally distributed
\n" ); document.write( " with population standard deviation of 200.
\n" ); document.write( "n = 100, x̄ = 650
\n" ); document.write( "(a)
\n" ); document.write( "Find a 95% confidence interval estimate of The mean SAT math score for HS seniors\r
\n" ); document.write( "\n" ); document.write( "Population SD Known: will use a z score analysis:
\n" ); document.write( " z = invNorm((1-.95)/2) = invNorm(.05)
\n" ); document.write( "critical value equal to z = 1.96\r
\n" ); document.write( "\n" ); document.write( "|
\n" ); document.write( "(b )
\n" ); document.write( "ME =\"+z%2Asigma%2Fsqrt%28n%29\"
\n" ); document.write( "ME = 1.96(200/10) = 39.2
\n" ); document.write( "650 ± 39.2
\n" ); document.write( "We are 95% confident that the mean SAT math score for the seniors is:
\n" ); document.write( "between 614.8 and 689.2
\n" ); document.write( "Check Arithmetic
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\n" ); document.write( "(c) Is a 90% confidence interval estimate of the mean SAT math score wider
\n" ); document.write( "than the 95% confidence interval estimate you got from part (b)? NO
\n" ); document.write( "Why? 90% confidence interval z = 1.645 (which is <1.96 Multiplying by smaller number)
\n" ); document.write( "Less accuracy, smaller interval
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