document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050987>Question 1050987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pressure of a gas container varies directly with its temperature and inversely with its volume. At a temperature of 70 Kelvin and a volume of 10 cubic meters, the pressure is 33.6 newtons per square meter. What is the pressure if the temperature is increased to 80 Kelvin and the volume is decreased to 6 cubic meters?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666621 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A pressure of a gas container varies directly with its temperature and inversely with its volume. At a temperature of 70 Kelvin and a volume of 10 cubic meters, the pressure is 33.6 newtons per square meter. What is the pressure if the temperature is increased to 80 Kelvin and the volume is decreased to 6 cubic meters? <BR>\n" );
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document.write( "PV = nRT<BR>\n" );
document.write( "PV = kT (k is a constant)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "P = kT/V<BR>\n" );
document.write( "33.6 = k*70/10<BR>\n" );
document.write( "k = 4.8<BR>\n" );
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document.write( "P = 4.8*80/6<BR>\n" );
document.write( "P = 64 (same units) </SPAN>\n" );
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