document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051034>Question 1051034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I need to rewrite this expression in terms of tanx: cscx/cotx - cotx/1+cscx<BR>\n" );
document.write( "So far I've gotten to (1/sinx)/(1/tanx) - (1/tanx)/(1+1/sinx)<BR>\n" );
document.write( "Any help is much appreciated </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666618 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, I need to rewrite this expression in terms of tanx: cscx/cotx - cotx/1+cscx<BR>\n" );
document.write( "So far I've gotten to (1/sinx)/(1/tanx) - (1/tanx)/(1+1/sinx)<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "= tan/sin - (1/tan)/((sin + 1)/sin)<BR>\n" );
document.write( "= tan/sin - sin/(tan*(sin+1))<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "sin = ątan/sqrt(1+tan^2)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "--> 1/sqrt(1+tan^2) - sqrt(1+tan^2)/(1 + tan/sqrt(1 + tan^2))<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "IDK what the point is. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );