document.write( "Question 1050961:
\n" ); document.write( "Suppose that a cyclist began a 476
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\n" ); document.write( "mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 8.5
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\n" ); document.write( "hr and the car traveled 39.6
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\n" ); document.write( "mph faster than the​ bicycle, find the average rate of each.
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Algebra.Com's Answer #666595 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Hint: The car travelled 39.6 times 8.5 miles farther than the bicycle and the sum of the distances travelled is 476. Average speed is distance travelled divided by the time.\r
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\n" ); document.write( "\n" ); document.write( "So\r
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\n" ); document.write( "\n" ); document.write( "Solve for . Then divide by 8.5 to find the average speed of the bicycle. The average speed of the car is 39.6 mph faster than that.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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