document.write( "Question 1050947: A certain virus infects one in every 400 people. A test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus. Let A be the event \"the person is infected\" and B be the event \"the person tests negative.\"\r
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document.write( "(a) Find the probability that a person has the virus given that they have tested positive.\r
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document.write( "(b) Find the probability that a person does not have the virus given that they have tested negative. \n" );
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Algebra.Com's Answer #666550 by EliteCracker(4)![]() ![]() ![]() You can put this solution on YOUR website! 90% of 100% = 9/10\r \n" ); document.write( "\n" ); document.write( "Answer to part A is \n" ); document.write( "\n" ); document.write( "10% of 100% = 1/10\r \n" ); document.write( "\n" ); document.write( "Answer to part B is \n" ); document.write( "\n" ); document.write( "CHECK \n" ); document.write( "----- \n" ); document.write( "90% of 400 = 360 infected people \n" ); document.write( "360/400 = 9/10 \n" ); document.write( "Every 9 of 10 people are infected.\r \n" ); document.write( "\n" ); document.write( "10% of 400 = 40 infected people \n" ); document.write( "40/400 = 1/10 \n" ); document.write( "Every 1 of 10 people are not infected. \n" ); document.write( " |