document.write( "Question 1050946: I'm stuck on this one!
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document.write( "The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm.
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document.write( "A) Find the probability that an individual distance is greater than 217.50 cm.
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document.write( "B) find the probability that the mean for 25 randomly selected distances is greater than 202.80 cm. \n" );
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Algebra.Com's Answer #666544 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 205 cm and a standard deviation of 8.3 cm. \n" ); document.write( "a. \n" ); document.write( "P(x>217.5) = 1 - P(x <= 217.5) \n" ); document.write( "z = (217.50-205)/8.3 = 1.5 \n" ); document.write( "P(z<=1.5) = normalcdf(-10,1.5)= .84 \n" ); document.write( "P(x > 217.5) = 1 - .84 = .16 0r 16% \n" ); document.write( "| \n" ); document.write( "b. n = 25 , x̄ = 202.8\r \n" ); document.write( "\n" ); document.write( "P(x>202.80) = 1 - P(x <= 202.80) \n" ); document.write( "z = \n" ); document.write( "P(z <= -1.3253) = .1885 \n" ); document.write( "|P(x > 202.8) = 1 - .1885 = .9115 0r 91.15% \n" ); document.write( "Check Arithmetic\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |