document.write( "Question 1050946: I'm stuck on this one!
\n" ); document.write( "The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm.
\n" ); document.write( "A) Find the probability that an individual distance is greater than 217.50 cm.
\n" ); document.write( "B) find the probability that the mean for 25 randomly selected distances is greater than 202.80 cm.
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Algebra.Com's Answer #666544 by ewatrrr(24785)\"\" \"About 
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205 cm and a standard deviation of 8.3 cm.
\n" ); document.write( "a. \"z+=blue+%28x+-+mu%29%2Fblue%28sigma%29\"
\n" ); document.write( "P(x>217.5) = 1 - P(x <= 217.5)
\n" ); document.write( "z = (217.50-205)/8.3 = 1.5
\n" ); document.write( "P(z<=1.5) = normalcdf(-10,1.5)= .84
\n" ); document.write( "P(x > 217.5) = 1 - .84 = .16 0r 16%
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\n" ); document.write( "b. n = 25 , x̄ = 202.8\r
\n" ); document.write( "\n" ); document.write( "P(x>202.80) = 1 - P(x <= 202.80)
\n" ); document.write( "z = \"z+=blue+%28202.80+-+205%29%2Fblue%288.3%2Fsqrt%2825%29%29\" = -2.2/1.66 = -1.3253
\n" ); document.write( "P(z <= -1.3253) = .1885
\n" ); document.write( "|P(x > 202.8) = 1 - .1885 = .9115 0r 91.15%
\n" ); document.write( "Check Arithmetic\r
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