document.write( "Question 1050865: What is 1-2+3-4+5-6+...+2013?\r
\n" ); document.write( "\n" ); document.write( "I have no idea how to do this problem. The answer is 1007\r
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Algebra.Com's Answer #666509 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"1-2%2B3-4%2B5-6\"+...+\"2013\"....take a look at signs: positive, negative, positive,negative..
\n" ); document.write( "\"odd\" integers are positive and \"even\" integers are negative\r
\n" ); document.write( "\n" ); document.write( "there is \"2013\" integers in all
\n" ); document.write( "since first and last \"odd\" integers, means there is \"one\"\"+even\" integer \"less\" than odd\r
\n" ); document.write( "\n" ); document.write( "since \"2013\" is not divisible by \"2\" we can write it as \"1007%2B1006+\" where \"1007\" are odd integers and \"1006\" even integer
\n" ); document.write( "since even integers are negative\r
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\n" ); document.write( "\n" ); document.write( "SUM OF EVEN NUMBERS: \"n%5Be%5D%28n%5Be%5D%2B1%29\"
\n" ); document.write( "SUM OF ODD NUMBERS: \"n%5Bo%5D%5E2\"\r
\n" ); document.write( "\n" ); document.write( "since \"even\" integers are negative, we subtract the sum of even from the sum of odd integers
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\n" ); document.write( "\"n%5Bo%5D%5E2-n%5Be%5D%28n%5Be%5D%2B1%29\"...........\"n%5Be%5D=1006\" and \"n%5Bo%5D=1007\" and we have
\n" ); document.write( "=\"+1007%5E2-1006%281006%2B1%29\"
\n" ); document.write( "=\"1007%5E2-1006%281006%2B1%29\"
\n" ); document.write( "=\"1014049-1006%5E2-1006\"
\n" ); document.write( "=\"1014049++-1012036-1006\"
\n" ); document.write( "=\"1014049++-1013042\"
\n" ); document.write( "=\"1007\"\r
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