document.write( "Question 1050894:
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document.write( "Find three consecutive odd integers such that the square of the third integer plus the product of the other two integers is 268.
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document.write( "(x+4)^2+x(x+2)=268
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document.write( "x^2+8x+16+x^2+2x=268
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document.write( "2x^2+10x+16=268
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document.write( "x^2+5x+8=134
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document.write( "x^2+5x-126=0
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document.write( "(x+9)(x+14)=0
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document.write( "x=9,x=-14
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document.write( "ingegers=9,11,13\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #666502 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! (x+4)^2+x(x+2)=268 \n" ); document.write( "x^2+8x+16+x^2+2x=268 \n" ); document.write( "2x^2+10x+16=268 \n" ); document.write( "x^2+5x+8=134 \n" ); document.write( "x^2+5x-126=0 \n" ); document.write( "(x-9)(x+14)=0 Note: Just the sign here \n" ); document.write( "x=9, x=-14 (discard) \n" ); document.write( "three consecutive odd integers = 9,11,13 \n" ); document.write( "checking \n" ); document.write( "169 + 99 = 268 CHECKS! \n" ); document.write( "Good work. \n" ); document.write( " |