document.write( "Question 1050894:
\n" ); document.write( "Wondering if I'm right...\r
\n" ); document.write( "\n" ); document.write( "Find three consecutive odd integers such that the square of the third integer plus the product of the other two integers is 268.
\n" ); document.write( "(x+4)^2+x(x+2)=268
\n" ); document.write( "x^2+8x+16+x^2+2x=268
\n" ); document.write( "2x^2+10x+16=268
\n" ); document.write( "x^2+5x+8=134
\n" ); document.write( "x^2+5x-126=0
\n" ); document.write( "(x+9)(x+14)=0
\n" ); document.write( "x=9,x=-14
\n" ); document.write( "ingegers=9,11,13\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #666502 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
(x+4)^2+x(x+2)=268
\n" ); document.write( "x^2+8x+16+x^2+2x=268
\n" ); document.write( "2x^2+10x+16=268
\n" ); document.write( "x^2+5x+8=134
\n" ); document.write( "x^2+5x-126=0
\n" ); document.write( "(x-9)(x+14)=0 Note: Just the sign here
\n" ); document.write( "x=9, x=-14 (discard)
\n" ); document.write( "three consecutive odd integers = 9,11,13
\n" ); document.write( "checking
\n" ); document.write( "169 + 99 = 268 CHECKS!
\n" ); document.write( "Good work.
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