document.write( "Question 1050837: (1/3)log[2]x = -3
\n" ); document.write( "I need to know x.\r
\n" ); document.write( "\n" ); document.write( "I tried the following:
\n" ); document.write( "(1/3)log[2] x = log 1/1000
\n" ); document.write( "log[2] x/3 = log 1/1000
\n" ); document.write( "{(log x/3) / (log 2) } = log 1/1000
\n" ); document.write( "I'm stuck here, am I doing something wrong?
\n" ); document.write( "

Algebra.Com's Answer #666442 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
(1/3)log[2]x = -3
\n" ); document.write( "I need to know x.\r
\n" ); document.write( "\n" ); document.write( "I tried the following:
\n" ); document.write( "(1/3)log[2] x = log 1/1000
\n" ); document.write( "log[2] x/3 = log 1/1000
\n" ); document.write( "{(log x/3) / (log 2) } = log 1/1000
\n" ); document.write( "I'm stuck here, am I doing something wrong?
\n" ); document.write( "----------------------
\n" ); document.write( "(1/3)log[2]x = -3
\n" ); document.write( "If it's (1/3)log(2)*x = -3
\n" ); document.write( "Then x = -9/log(2) =~ -29.897
\n" ); document.write( "----------
\n" ); document.write( "If it's \"log%282%2Cx%29\" :
\n" ); document.write( "\"log%282%2Cx%29+=+-9+=+log%282%2C2%5E-9%29\"
\n" ); document.write( "\"x+=+2%5E-9\"
\n" ); document.write( "x = 1/512\r
\n" ); document.write( "\n" ); document.write( "
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