document.write( "Question 1050790: consider the following probability distribution
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document.write( "x -4 0 1 3
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document.write( "p(x) .1 .2 .4 .3\r
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document.write( "a. list the values that x may assume.
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document.write( "b. what value of x is most probable?
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document.write( "c. what is the probability that x is greater than 0?
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document.write( "d. what is the probability that x = -2 \n" );
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Algebra.Com's Answer #666432 by robertb(5830)![]() ![]() You can put this solution on YOUR website! a. -4, 0, 1, 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b. x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c. p(x > 0) = 0.4 + 0.3 = 0.7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d. p(x = -2) = 0. \n" ); document.write( " |