document.write( "Question 91042: n+4/9=3
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Algebra.Com's Answer #66641 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
A couple of ways come to mind on this problem.
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\n" ); document.write( "You are given:
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\n" ); document.write( "\"n%2B4%2F9=3\"
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\n" ); document.write( "To solve for n, you might replace the 3 on the right side by \"27%2F9\" which is equal to 3.
\n" ); document.write( "Note that this fraction has the same denominator as the fraction on the left side.
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\n" ); document.write( "Next you can get rid of the \"4%2F9\" on the left side by subtracting \"4%2F9\" from both
\n" ); document.write( "sides. This subtraction results in:
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\n" ); document.write( "\"n+=+27%2F9+-+4%2F9\"
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\n" ); document.write( "Because the fractions on the right side have the same denominator you can subtract their
\n" ); document.write( "numerators and the equation reduces to:
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\n" ); document.write( "\"n+=+%2827-4%29%2F9+=+23%2F9\"
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\n" ); document.write( "So, you have the answer of \"n+=+23%2F9\"
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\n" ); document.write( "Another way you could do the problem is to start with the original equation:
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\n" ); document.write( "\"n%2B4%2F9=3\"
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\n" ); document.write( "and get rid of the denominator 9 by multiplying both sides (all terms) by 9. This multiplication
\n" ); document.write( "results in:
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\n" ); document.write( "\"9n+%2B+%289%2A4%29%2F9+=+9%2A3\"
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\n" ); document.write( "And this simplifies to:
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\n" ); document.write( "\"9n+%2B+4+=+27\"
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\n" ); document.write( "Subtract 4 from both sides and you have:
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\n" ); document.write( "\"9n+=+23\"
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\n" ); document.write( "And finally, solve for n by dividing both sides by 9 (the multiplier of n) to get:
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\n" ); document.write( "\"n+=+23%2F9\"
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\n" ); document.write( "Which is the same answer as we got before.
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\n" ); document.write( "You can check the answer by returning to the original equation you were given and substituting
\n" ); document.write( "\"23%2F9\" for n to get:
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\n" ); document.write( "\"23%2F9+%2B+4%2F9+=+3\"
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\n" ); document.write( "On the left side, there is a common denominator so the numerators can be added to get:
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\n" ); document.write( "\"%2823%2B4%29%2F9+=+3\"
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\n" ); document.write( "After the numerators are added you have:
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\n" ); document.write( "\"27%2F9+=+3\"
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\n" ); document.write( "And after the 27 is divided by the 9 on the left side you get:
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\n" ); document.write( "\"3+=+3\"
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\n" ); document.write( "Since this is true, the equation works when \"n+=+23%2F9\". Therefore, the answer we
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\n" ); document.write( "Hope this helps you to understand the problem and several ways in which it can be worked.
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\n" ); document.write( "And just in case you meant the problem to be:
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\n" ); document.write( "\"%28n+%2B+4%29%2F9+=+3\"
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\n" ); document.write( "(which is not the way you wrote it), you can work this problem by multiplying both sides
\n" ); document.write( "by 9 (all terms) to make the equation become:
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\n" ); document.write( "\"n+%2B+4+=+27\"
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\n" ); document.write( "Then subtract 4 from both sides and you get:
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\n" ); document.write( "\"n+=+27+-+4+=+23\"
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\n" ); document.write( "In this case the answer for n is n = 23.
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