document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13270>Question 13270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of two supplementary angles measures 37 degrees less than four times the other. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6664 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know supplementary angles add up to 180 degrees<BR>\n" );
document.write( "so for angle 1 (a1) and angle 2 (a2)<BR>\n" );
document.write( "we have a1+a2=180 and a1=4a2-37<BR>\n" );
document.write( "sub a1 in the first equation to get<BR>\n" );
document.write( "4a2-37+a2=180<BR>\n" );
document.write( "add 37 to both sides to get<BR>\n" );
document.write( "5a2=217<BR>\n" );
document.write( "divide both sides bt 5<BR>\n" );
document.write( "a2=43.4<BR>\n" );
document.write( "now sub this back in the first equation<BR>\n" );
document.write( "a1=180-a2=180-43.4=136.6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );