document.write( "Question 1050765: if you want to travel an average of 50/mi per hour on a trip and half of the trip you go 25/mi per hour how fast do you have to travel in the second half \n" ); document.write( "

Algebra.Com's Answer #666387 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!
How do you measure the trip? Distance?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Try that.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Constant Travel Rate Rule is as D/T=R, D for distance and T for time.
\n" ); document.write( " $\"T%2FD=1%2FR\"$
\n" ); document.write( " $\"T=D%2FR\"$ \r
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "              RATE      TIME     DISTANCE\r\n" );
document.write( "\r\n" );
document.write( "First          25              d \r\n" );
document.write( "\r\n" );
document.write( "Second          r               d\r\n" );
document.write( "\r\n" );
document.write( "Total                      2d\r\n" );
document.write( "\r\n" );
document.write( "AVERAGE        50\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Average rate is given and time sum will give $\"%282d%29%2F%28d%2F25%2Bd%2Fr%29=50\"$ .
\n" ); document.write( "Two variables in one equation but simplification will change that. \n" ); document.write( "

\n" );