document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050764>Question 1050764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> assuming that six times the measure of one angle of a pair of complementary angles is thirty degrees more than four times the measure of the other angle find the measure of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666382 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  assuming that six times the measure of one angle of a pair of complementary angles is thirty degrees more than four times the measure of the other angle find the measure of the angles <BR>\n" );
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document.write( "1st:: x<BR>\n" );
document.write( "2nd:: 90-x<BR>\n" );
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document.write( "6(90-x) = 4x+30<BR>\n" );
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document.write( "540 - 6x = 4x + 30<BR>\n" );
document.write( "510 = 10x<BR>\n" );
document.write( "x = 51 degrees<BR>\n" );
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document.write( "90-x = 39 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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