document.write( "Question 1050687: Please help me solved this math now. Find the equation of
\n" ); document.write( "a circle tangent to the line 2x - 3y = -7 at (1,3) passing
\n" ); document.write( "through (11, 1).
\n" ); document.write( "

Algebra.Com's Answer #666379 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "
\r\n" );
document.write( "The red line is the given line 2x-3y = -7,\r\n" );
document.write( "The green and blue lines are radii of the circle.\r\n" );
document.write( "\r\n" );
document.write( "We need the slope of the given red line so we can get \r\n" );
document.write( "the equation of the green line, which is perpendicular\r\n" );
document.write( "to it:\r\n" );
document.write( "\r\n" );
document.write( "   2x-3y = 7\r\n" );
document.write( "     -3y = -2x+7\r\n" );
document.write( "       \"y\"\"%22%22=%22%22\"\"expr%28%28-2%29%2F%28-3%29%29x%2Bexpr%287%2F%28-3%29%29\"\r\n" );
document.write( "       \"y\"\"%22%22=%22%22\"\"expr%282%2F3%29x-7%2F3\" <--equation of red line\r\n" );
document.write( "\r\n" );
document.write( "Comparing to y = mx+b, slope of red line = \"2%2F3\"\r\n" );
document.write( "The green line is perpendicular to the red line, so\r\n" );
document.write( "the green line's slope is the negative reciprocal of\r\n" );
document.write( "\"2%2F3\" which is \"-3%2F2\".\r\n" );
document.write( "\r\n" );
document.write( "The green line passes through (1,3), so we use the point-\r\n" );
document.write( "slope formula to find its equation\r\n" );
document.write( "\r\n" );
document.write( "\"y-y%5B1%5D\"\"%22%22=%22%22\"\"m%28x-x%5B1%5D%29\"\r\n" );
document.write( "\"y-3\"\"%22%22=%22%22\"\"expr%28-3%2F2%29%28x-1%29\"\r\n" );
document.write( "clear fraction by multiplyng through by 2\r\n" );
document.write( "\"2y-6\"\"%22%22=%22%22\"\"-3%28x-1%29\"\r\n" );
document.write( "\"2y-6\"\"%22%22=%22%22\"\"-3x%2B3\"\r\n" );
document.write( "\"3x%2B2y\"\"%22%22=%22%22\"\"9\"  <-- eq. of the green line \r\n" );
document.write( "\r\n" );
document.write( "The center of the circle (h,k) is a point on\r\n" );
document.write( "the green line, so we substitute (x,y) = (h,k)\r\n" );
document.write( "\r\n" );
document.write( "eq. 1:   \"3h%2B2k\"\"%22%22=%22%22\"\"9\"\r\n" );
document.write( "\r\n" );
document.write( "We use the distance formula to find an expression\r\n" );
document.write( "for the length of the green and blue lines, which\r\n" );
document.write( "will be the radius, so\r\n" );
document.write( "\r\n" );
document.write( "\"sqrt%28%28h-1%29%5E2%2B%28k-3%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28h-11%0D%0A%29%5E2%2B%28k-1%29%5E2%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cthe%2Cradius%2Cr%29\"\r\n" );
document.write( "\r\n" );
document.write( "Square both sides:\r\n" );
document.write( "\r\n" );
document.write( "\"%28h-1%29%5E2%2B%28k-3%29%5E2\"\"%22%22=%22%22\"\"%28h-11%0D%0A%29%5E2%2B%28k-1%29%5E2\"\r\n" );
document.write( "\r\n" );
document.write( "\"h%5E2-2h%2B1%2Bk%5E2-6k%2B9\"\"%22%22=%22%22\"\"h%5E2-22h%2B121%2Bk%5E2-2k%2B1\"\r\n" );
document.write( "\r\n" );
document.write( "\"h%5E2-2h%2B10%2Bk%5E2-6k\"\"%22%22=%22%22\"\"h%5E2-22h%2B122%2Bk%5E2-2k\"\r\n" );
document.write( "\r\n" );
document.write( "Simplify by cancelling h2's and k2's \r\n" );
document.write( "\r\n" );
document.write( "\"-2h%2B10-6k\"\"%22%22=%22%22\"\"-22h%2B122-2k\"\r\n" );
document.write( "\r\n" );
document.write( "\"20h-4k\"\"%22%22=%22%22\"\"112\"\r\n" );
document.write( "\r\n" );
document.write( "Divide through by 4\r\n" );
document.write( "\"5h-k\"\"%22%22=%22%22\"\"28\"\r\n" );
document.write( "\r\n" );
document.write( "So we put this with equation (1) above\r\n" );
document.write( "as a system of equations:\r\n" );
document.write( "\r\n" );
document.write( "\"system%285h-k=28%2C3h%2B2k=9%29\"\r\n" );
document.write( "\r\n" );
document.write( "Solve that system by substitution and get\r\n" );
document.write( "\r\n" );
document.write( "(h,k) = (5,-3)    <-- center of circle\r\n" );
document.write( "\r\n" );
document.write( "We find the radius from\r\n" );
document.write( "\r\n" );
document.write( "\"sqrt%28%28h-1%29%5E2%2B%28k-3%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28h-11%0D%0A%29%5E2%2B%28k-1%29%5E2%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cthe%2Cradius%2Cr%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"sqrt%28%285-1%29%5E2%2B%28-3-3%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%285-11%0D%0A%29%5E2%2B%28-3-1%29%5E2%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cthe%2Cradius%2Cr%29\"\r\n" );
document.write( " \r\n" );
document.write( "\"sqrt%28%284%29%5E2%2B%28-6%29%5E2%29\"\"%22%22=%22%22\"\"sqrt%28%28-6%0D%0A%29%5E2%2B%28-4%29%5E2%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cthe%2Cradius%2Cr%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"sqrt%2816%2B36%29\"\"%22%22=%22%22\"\"sqrt%2836%2B16%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cthe%2Cradius%2Cr%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"sqrt%2852%29\"\"%22%22=%22%22\"\"sqrt%2852%29\"\"%22%22=%22%22\"\"matrix%281%2C3%2Cthe%2Cradius%2Cr%29\"\r\n" );
document.write( "\r\n" );
document.write( "So the radius is \"sqrt%2852%29\"\r\n" );
document.write( "\r\n" );
document.write( "Equation of circle:\r\n" );
document.write( "\r\n" );
document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2\"\"%22%22=%22%22\"\"r%5E2\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28x-5%5E%22%22%29%5E2%2B%28y-%28-3%29%5E%22%22%29%5E2\"\"%22%22=%22%22\"\"%28sqrt%2852%29%29%5E2\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28x-5%29%5E2%2B%28y%2B3%29%5E2\"\"%22%22=%22%22\"\"52\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );