document.write( "Question 1050730: Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance between A and B? \n" ); document.write( "
Algebra.Com's Answer #666372 by advanced_Learner(501) You can put this solution on YOUR website! Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance between A and B?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cycle \n" ); document.write( "speed 20 \n" ); document.write( "time t \n" ); document.write( "distance 20t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cycle back \n" ); document.write( "speed 18 \n" ); document.write( "time 19/12-t \n" ); document.write( "distance 18(19/12-t)\r \n" ); document.write( "\n" ); document.write( "20t=18(19/12-t) \n" ); document.write( "20t=(3*19)/2-18t \n" ); document.write( "t=(3*19)/2\r \n" ); document.write( "\n" ); document.write( "t= \n" ); document.write( "\n" ); document.write( "now calculate the distance \n" ); document.write( "20(57/76)=distance \n" ); document.write( "15km=Distance \n" ); document.write( " |