document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050730>Question 1050730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance between A and B?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666365 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, 1 hour,35 minutes equals 1-35/60 hours, or 1-7/12 hours, equaling 19/12 hours total. Let n be the amount of time for the trip from A to B. Then:<BR>\n" );
document.write( "20n=18(19/12-n)<BR>\n" );
document.write( "20n=342/12-18n<BR>\n" );
document.write( "38n=57/2<BR>\n" );
document.write( "n=57/76<BR>\n" );
document.write( "20 km/h x (57/76)hrs. =15 kilometers between A and B. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
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