document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91757>Question 91757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve: 2^(2x+1) = 3^(2x+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66630 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve: 2^(2x+1) = 3^(2x+2)\r<BR>\n" );
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document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(2x+1)log2 = (2x+2)log3<BR>\n" );
document.write( "2x log 2 - 2xlog3 = 2log3 - log2<BR>\n" );
document.write( "x = [2log3 - log2]/[2log2 -2log3]<BR>\n" );
document.write( "x = -1.8548<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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