document.write( "Question 1050269: A goat is tied outside the fence of a 5-m diameter circular garden using a 3-m rope. One end of the rope is tied to the collar around the neck of the goat and the other s attached to the fence at the point which is at the level as the goat's collar (the goat can move anywhere within 3 meters from the outside of the circular fence). Find the area by which the goat can move around by integration. \n" ); document.write( "
Algebra.Com's Answer #666290 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "The red circle is the circular garden. \n" ); document.write( "The purple circle is the 3m radius from the edge of the circular garden fence. \n" ); document.write( "The equations of the two circles are, \n" ); document.write( " \n" ); document.write( "1. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "To find the intersection points substitute from eq. 1 into eq. 2, \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So then integrate to get the sliver area (shown in green), \n" ); document.write( "the limits of integration would be \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Double that plus half of the area of the large circle will be the complete area that the goat can graze, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |