document.write( "Question 1050269: A goat is tied outside the fence of a 5-m diameter circular garden using a 3-m rope. One end of the rope is tied to the collar around the neck of the goat and the other s attached to the fence at the point which is at the level as the goat's collar (the goat can move anywhere within 3 meters from the outside of the circular fence). Find the area by which the goat can move around by integration. \n" ); document.write( "
Algebra.Com's Answer #666290 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "The red circle is the circular garden.
\n" ); document.write( "The purple circle is the 3m radius from the edge of the circular garden fence.
\n" ); document.write( "The equations of the two circles are,
\n" ); document.write( "\"x%5E2%2By%5E2=%282.5%29%5E2\"
\n" ); document.write( "1.\"x%5E2%2By%5E2=6.25\"
\n" ); document.write( "\"%28x-2.5%29%5E2%2By%5E2=%283%29%5E2\"
\n" ); document.write( "\"%28x-2.5%29%5E2%2By%5E2=9\"
\n" ); document.write( "To find the intersection points substitute from eq. 1 into eq. 2,
\n" ); document.write( "\"y%5E2=6.25-x%5E2\"
\n" ); document.write( "So,
\n" ); document.write( "\"%28x-2.5%29%5E2%2B6.25-x%5E2=9\"
\n" ); document.write( "\"x%5E2-5x%2B6.25%2B6.25-x%5E2=9\"
\n" ); document.write( "\"x%5E2-5x%2B12.5-x%5E2=9\"
\n" ); document.write( "\"-5x=-3.5\"
\n" ); document.write( "\"x=0.7\"
\n" ); document.write( "So then integrate to get the sliver area (shown in green),
\n" ); document.write( "the limits of integration would be \"x=0.7\" and \"x=2.5\".
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\n" ); document.write( "\"A=int%28%28y%5B2%5D-y%5B1%5D%29%2Cdx%2Cx=0.7%2C2.5%29\"
\n" ); document.write( "\"A=int%28%28sqrt%289-%28x-2.5%29%5E2%29-sqrt%286.25-x%5E2%29%29%2Cdx%2Cx=0.7%2C2.5%29\"
\n" ); document.write( "\"A=1.874\" <-- Obtained numerically
\n" ); document.write( "Double that plus half of the area of the large circle will be the complete area that the goat can graze,
\n" ); document.write( "\"A%5Btot%5D=2%281.874%29%2B%28pi%283%29%5E2%29%2F2\"
\n" ); document.write( "\"A%5Btot%5D=17.89\"
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