document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050680>Question 1050680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jacky is twice as old as lacy. In three years the sum is f their ages will be 54. Find their present  age  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666262 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x Lacy's age, Jacky 2x<BR>\n" );
document.write( "Question States<BR>\n" );
document.write( "(x+3) + (2x+3) = 54<BR>\n" );
document.write( "3x+ 6 = 54<BR>\n" );
document.write( "3x = 16<BR>\n" );
document.write( "x = 16, Lacy's age.  Jacky 32<BR>\n" );
document.write( "and<BR>\n" );
document.write( "in 3 years<BR>\n" );
document.write( "19 + 35 = 54 CHECKS! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );