document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050593>Question 1050593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ling invested some money at <BR>\n" );
document.write( "7%<BR>\n" );
document.write( "interest. Ling also invested <BR>\n" );
document.write( "$137<BR>\n" );
document.write( "more than <BR>\n" );
document.write( "3<BR>\n" );
document.write( "times that amount at <BR>\n" );
document.write( "14%<BR>\n" );
document.write( ". How much is invested at each rate if Ling receives <BR>\n" );
document.write( "$1489.18<BR>\n" );
document.write( "in interest after one year? (Round to two decimal places if necessary.)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666226 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.07x+0.14(3x+137) = 1489.18<BR>\n" );
document.write( "0.07x+0.42x+19.18 = 1489.18<BR>\n" );
document.write( "0.49x = 1470<BR>\n" );
document.write( "x = 3000 is invested at 7%<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(3*3000)+137 = 9137 is invested at 14% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );