document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050649>Question 1050649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an experienced roofer can work twice as fast as helper. working together, they can shingle a new section of roof in 4 h. how long would it take the experienced roofer, working alone, to complete the same job </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666217 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> takes the experienced rooster x hours, the other 2x hours<BR>\n" );
document.write( "in 1 hour, the experienced roofer does 1/x of the house, the inexperienced 1/2x hours<BR>\n" );
document.write( "in 4 hours, the experienced does 4/x and the other 4/2x of the house.<BR>\n" );
document.write( "That finishes it, so the two add to 1<BR>\n" );
document.write( "(4/x)+(4/2x)=1<BR>\n" );
document.write( "multiply everything by 2x<BR>\n" );
document.write( "8+4=2x<BR>\n" );
document.write( "2x=12<BR>\n" );
document.write( "x=6 hours for the experienced one alone  ANSWER<BR>\n" );
document.write( "12 hours for the other<BR>\n" );
document.write( "together (4/6)+(4/12)=1 </SPAN>\n" );
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