document.write( "Question 1050644: If man rows a boat 500feet upstream against constant current in 10min,while return trip cover 300feet in 5 mins, find speed of current and and equivalent rate at which he can row in still water? \n" ); document.write( "
Algebra.Com's Answer #666211 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let r be the rate of the man's rowing and c be the rate of the current, then \n" ); document.write( ": \n" ); document.write( "1) (r-c) * 10 = 500 \n" ); document.write( ": \n" ); document.write( "2) (r+c) * 5 = 300 \n" ); document.write( ": \n" ); document.write( "solve equation 1 for c \n" ); document.write( ": \n" ); document.write( "10r -10c = 500 \n" ); document.write( ": \n" ); document.write( "c = (10r - 500) / 10 = r - 50 \n" ); document.write( ": \n" ); document.write( "substitute for c in equation 2 \n" ); document.write( ": \n" ); document.write( "(r + r - 50) * 5 = 300 \n" ); document.write( ": \n" ); document.write( "10r - 250 = 300 \n" ); document.write( ": \n" ); document.write( "10r = 550 \n" ); document.write( ": \n" ); document.write( "r = 55 feet per minute \n" ); document.write( ": \n" ); document.write( "c = 55 - 50 = 5 feet per minute \n" ); document.write( ": \n" ); document.write( "****************************** \n" ); document.write( "man rows at 55 feet per minute \n" ); document.write( "current is 5 feet per minute \n" ); document.write( "****************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |