document.write( "Question 1050433: Prove that if k is an integer then (4k+1)i^4k + (4k+2)i^4k+1 + (4k+3)i^4k+2 + (4k+4)i^4k+3= 2-2i.
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document.write( "Use this to prove that
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document.write( "1+2i+3i^2+4i^3+...+1995i^1994+1996i^1995=-998-998i \n" );
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Algebra.Com's Answer #666209 by robertb(5830)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "===> \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now substitute the values of k = 0, 1, 2, 3,...,497, 498 into the formula.\r \n" ); document.write( "\n" ); document.write( "On the left side of the equation, we would get\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "while on the right side, we would get\r \n" ); document.write( "\n" ); document.write( "499*(-2 - 2i) = -998 - 998i.\r \n" ); document.write( "\n" ); document.write( "Therefore,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |