document.write( "Question 1050626: i am having trouble with theese 2\r
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document.write( "1: y = g(x) = -2x^2 - 6x\r
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document.write( "2: The demand function for an electronics company's laptop computer line is p = 2400 - 6q , where p is the price (in dollars) per unit when q units are demanded (per week. Find the level of production that maximizes the manufacturer's total revenue and determine this revenue. \n" );
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Algebra.Com's Answer #666205 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 1. g(x) = -2x^2 - 6x \n" ); document.write( "Completing Square: \n" ); document.write( "g(x) = -2(x^2 - 3x) \n" ); document.write( "g(x) = -2(x^2 - 3x + (3/2)^2) + 2(3/2)^2 \n" ); document.write( "g(x) = -2(x - 3/2)^2 + 9/2 \n" ); document.write( "| \n" ); document.write( "Revenue functions R(x) = px where p is a function of x (price p at x produced, for ex.) \n" ); document.write( "2. \n" ); document.write( "p = 2400 - 6q \n" ); document.write( "R(q) = (2400-6q)q \n" ); document.write( "R(q) = -6q^2)+ 2400q \n" ); document.write( "Completing Square: \n" ); document.write( "R(q) = -6(q^2 - 400q) \n" ); document.write( "R(q) = -6(q^2 - 400q + 200^2)+ 6(200^2) \n" ); document.write( "R(q) = -6(q - 200)^2 + 6(200^2) Parabola Opening Downward V(200, 240,000) \n" ); document.write( "q = 200 maximizes Revenue = $240,000\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |