document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91724>Question 91724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help with this one:  Solve by completing the square.  Thank you :)\r<BR>\n" );
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document.write( "x^2-1/2x-3/16=0\r<BR>\n" );
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document.write( "answer choices:<BR>\n" );
document.write( "a. -1/4, 3/4<BR>\n" );
document.write( "b. -1/4, 2/3<BR>\n" );
document.write( "c. -3/4, 1/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66620 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> completing the square - step-by-step ... for ax^2+bx+c=0\r<BR>\n" );
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document.write( "1) by dividing or multiplying, set the coefficient of the squared term equal to one ... x^2+(b/a)x+(c/a)=0\r<BR>\n" );
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document.write( "2) by adding or subtracting, set the constant term (c/a) equal to zero ... x^2+(b/a)x=-(c/a)\r<BR>\n" );
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document.write( "3) add the square of one half of the x coefficient to both sides ... x^2+(b/a)x+(b/(2a))^2=-(c/a)+(b/(2a))^2\r<BR>\n" );
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document.write( "4) take the square root of both sides ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B%28b%2F%282a%29%29=sqrt%28%28b%5E2-4ac%29%2F%284a%5E2%29%29 ALIGN=MIDDLE  ALT=\"x%2B%28b%2F%282a%29%29=sqrt%28%28b%5E2-4ac%29%2F%284a%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > , realizing the root is positive AND negative\r<BR>\n" );
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document.write( "in this case, x-(1/4)=1/2 and x-(1/4)=-1/2 ... x=3/4 and -1/4 ... looks like (a) is it </SPAN>\n" );
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