document.write( "Question 1050294: Kevin has money in two savings accounts. One rate is 13% and the other is 14%. If he has $650 more in the 14% account and the total interest is $226, how much is invested in each savings account? \n" ); document.write( "
Algebra.Com's Answer #666087 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount invested at 13%. Then the amount invested at 14% is n+650. So: \n" ); document.write( ".13n+.14(n+650)=226 \n" ); document.write( ".27n=135 \n" ); document.write( "n=135/.27=500 \n" ); document.write( "$500 is invested at 13%; $1150 is invested at 14%. ☺☺☺☺ \n" ); document.write( " |