document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050442>Question 1050442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The compressive strength of cement can be modeled by a normal distribution with<BR>\n" );
document.write( "a mean of 6000 kilograms per square centimeter and a standard deviation of 100<BR>\n" );
document.write( "kilograms per centimeter.<BR>\n" );
document.write( "a. What is the probability that a sample’s strength is less than 6252 kg/cm2 ?<BR>\n" );
document.write( "b. What is the probability that a sample’s strength is between 5800 and 5890 kg/cm2 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #666060 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=666060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a mean of 6000 kilograms per square centimeter and a standard deviation of 100<BR>\n" );
document.write( "a) P = normalcdf(-9999, 6252, 6000, 100)<BR>\n" );
document.write( "b) P = normalcdf(5800, 5890, 6000, 100) <BR>\n" );
document.write( "In general:<BR>\n" );
document.write( "TI syntax is normalcdf(smaller, larger, µ, &#963;).<BR>\n" );
document.write( "Recommend Using stattrek.com to check  Results<BR>\n" );
document.write( "until You are familiar with Using Your Calculator.<BR>\n" );
document.write( "One could also Use Your Casio fx-115 ES plus 0r fx-991 ES plus <BR>\n" );
document.write( "ON, Mode(scroll down) , 3: DIST (choose type of function desired)<BR>\n" );
document.write( " </SPAN>\n" );
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