document.write( "Question 1050489: z varies directly as x3 and inversely as y3. If z = 132 when x = 9 and y = 3, find z if x = 10 and y = 9. \n" ); document.write( "
Algebra.Com's Answer #666052 by stanbon(75887)\"\" \"About 
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z varies directly as x^3 and inversely as y^3.
\n" ); document.write( "z = k*x^3/y^3
\n" ); document.write( "-----------------------
\n" ); document.write( "Solve for \"k\" if z = 132 when x = 9 and y = 3
\n" ); document.write( "132 = k*(9^3)/(3^3)
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\n" ); document.write( "132 = k*3^3
\n" ); document.write( "k = 4.89
\n" ); document.write( "------
\n" ); document.write( "Find z if x = 10 and y = 9.
\n" ); document.write( "z = 4.89*10^3/(9^3)
\n" ); document.write( "---
\n" ); document.write( "z = 6.71
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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