document.write( "Question 1050489: z varies directly as x3 and inversely as y3. If z = 132 when x = 9 and y = 3, find z if x = 10 and y = 9. \n" ); document.write( "
Algebra.Com's Answer #666052 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! z varies directly as x^3 and inversely as y^3. \n" ); document.write( "z = k*x^3/y^3 \n" ); document.write( "----------------------- \n" ); document.write( "Solve for \"k\" if z = 132 when x = 9 and y = 3 \n" ); document.write( "132 = k*(9^3)/(3^3) \n" ); document.write( "--- \n" ); document.write( "132 = k*3^3 \n" ); document.write( "k = 4.89 \n" ); document.write( "------ \n" ); document.write( "Find z if x = 10 and y = 9. \n" ); document.write( "z = 4.89*10^3/(9^3) \n" ); document.write( "--- \n" ); document.write( "z = 6.71 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |