document.write( "Question 1050495: Two cars start from towns 570 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 15 mph faster than the other. \n" ); document.write( "
Algebra.Com's Answer #666044 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = the speed of the slower car in mi/hr
\n" ); document.write( "\"+s+%2B+15+\" = the speed of the faster car in mi/hr
\n" ); document.write( "---------------------------
\n" ); document.write( "Think of this as one car standing still and the other
\n" ); document.write( "car moving at the sum of their speeds
\n" ); document.write( "-----------------------------------
\n" ); document.write( "\"+570+=+%28+s+%2B+s+%2B+15+%29%2A6+\"
\n" ); document.write( "\"+570++=+%28+2s+%2B+15+%29%2A6+\"
\n" ); document.write( "\"+570+=+12s+%2B+90+\"
\n" ); document.write( "\"+12s+=+480+\"
\n" ); document.write( "\"+s+=+40+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s%2B+15+=+55+\"
\n" ); document.write( "------------------
\n" ); document.write( "The faster car's speed is 55 mi/hr
\n" ); document.write( "The slower car's speed is 40 mi/hr
\n" ); document.write( "-------------------------------
\n" ); document.write( "check answers:
\n" ); document.write( "\"+d%5B1%5D+=+40%2A6+\"
\n" ); document.write( "\"+d%5B1%5D+=+240+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+55%2A6+\"
\n" ); document.write( "\"+d%5B2%5D+=+330+\" mi
\n" ); document.write( "------------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+240+%2B+330+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+570+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
\n" );