document.write( "Question 1050444: Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 57 hours and a standard deviation of 3.5 hours. With this information, answer the following questions.\r
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document.write( "(a) What proportion of light bulbs will last more than 62 hours?
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document.write( "(b) What proportion of light bulbs will last 53 hours or less?
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document.write( "(c) What proportion of light bulbs will last between 57 and 62 hours?
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document.write( "(d) What is the probability that a randomly selected light bulb lasts less than 45 hours?\r
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document.write( "How do I solve this using a TI calculator? \n" );
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Algebra.Com's Answer #666033 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean of 57 hours and a standard deviation of 3.5 hours. \n" ); document.write( "(a) What proportion of light bulbs will last more than 62 hours? \n" ); document.write( "TI syntax is P = normalcdf(smaller, larger, µ, σ) \n" ); document.write( "P = normalcdf(62, 9999, 57, 3.5) |Note: 9999 used as placeholder for larger \n" ); document.write( "(b) What proportion of light bulbs will last 53 hours or less? \n" ); document.write( "P = normalcdf(-9999,53, 57, 3.5) \n" ); document.write( "(c) What proportion of light bulbs will last between 57 and 62 hours? \n" ); document.write( "P = normalcdf(57,62, 57, 3.5) \n" ); document.write( "(d) What is the probability that a randomly selected light bulb lasts less than 45 hours? \n" ); document.write( "Since this is a continuous function, we have P(x < 45) = P(x ≤ 45). \n" ); document.write( "P = normalcdf(-9999,45, 57, 3.5) \n" ); document.write( " \n" ); document.write( " |