document.write( "Question 1050446: The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day.\r
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document.write( "(a) Determine the 16th percentile for incubation times.
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document.write( "(b) Determine the incubation times that make up the middle 97% of fertilized eggs.\r
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document.write( "How can I solve this (preferably) using a TI calculator? \n" );
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Algebra.Com's Answer #666030 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! a) z = invNorm(.16)-.9945 Use Your TI \n" ); document.write( " \n" ); document.write( "0r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "| \n" ); document.write( "b middle 97%: from .015 to .985 \n" ); document.write( "z = invNorm( 98.5)= 2.17 and invNorm(.015)= -2.17 \n" ); document.write( " P(-2.17 ≤ z ≤ 2.17). \n" ); document.write( "TI syntax is normalcdf(smaller z, larger z) \n" ); document.write( "P(-2.17 ≤ z ≤ 2.17) = normalcdf(-2.17, 2.17) Use Your TI\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |