document.write( "Question 1050425: The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle \n" ); document.write( "
Algebra.Com's Answer #665992 by advanced_Learner(501)\"\" \"About 
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The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle\r
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\n" ); document.write( "\n" ); document.write( "original rectangle\r
\n" ); document.write( "\n" ); document.write( "L-w=4
\n" ); document.write( "p=2L+2w
\n" ); document.write( "p=\"8%2B4w\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2w
\n" ); document.write( "L-2\r
\n" ); document.write( "\n" ); document.write( "p=\"2L-4%2B4w\"\r
\n" ); document.write( "\n" ); document.write( "then it says
\n" ); document.write( "2L+4w-4= 8+4w+8\r
\n" ); document.write( "\n" ); document.write( "L=10\r
\n" ); document.write( "\n" ); document.write( "original rec
\n" ); document.write( "L=10
\n" ); document.write( "W=6\r
\n" ); document.write( "\n" ); document.write( "check
\n" ); document.write( "your self!
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