document.write( "Question 1050425: The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle \n" ); document.write( "
Algebra.Com's Answer #665992 by advanced_Learner(501)![]() ![]() You can put this solution on YOUR website! The length of a rectangle exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle\r \n" ); document.write( "\n" ); document.write( "===========================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "original rectangle\r \n" ); document.write( "\n" ); document.write( "L-w=4 \n" ); document.write( "p=2L+2w \n" ); document.write( "p= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2w \n" ); document.write( "L-2\r \n" ); document.write( "\n" ); document.write( "p= \n" ); document.write( "\n" ); document.write( "then it says \n" ); document.write( "2L+4w-4= 8+4w+8\r \n" ); document.write( "\n" ); document.write( "L=10\r \n" ); document.write( "\n" ); document.write( "original rec \n" ); document.write( "L=10 \n" ); document.write( "W=6\r \n" ); document.write( "\n" ); document.write( "check \n" ); document.write( "your self! \n" ); document.write( " |