document.write( "Question 1050412: the boat goes downstream at 13 kph
\n" ); document.write( "upstream it goes three kph
\n" ); document.write( "what is the speed of the current?
\n" ); document.write( "It is obvious it is ten kph, but how do you put this into an equation?
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Algebra.Com's Answer #665978 by advanced_Learner(501)\"\" \"About 
You can put this solution on YOUR website!
u+v=13
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cu+%2B+1%5Cv+=+13%2C%0D%0A++++1%5Cu+%2B+-1%5Cv+=+3+%29%0D%0A++\"We'll use substitution. After moving 1*v to the right, we get:
\n" ); document.write( " \"1%2Au+=+13+-+1%2Av\", or \"u+=+13%2F1+-+1%2Av%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"1%2A%2813%2F1+-+1%2Av%2F1%29+%2B+-1%5Cv+=+3\" and simplify: So, we know that v=5. Since \"u+=+13%2F1+-+1%2Av%2F1\", u=8.
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\n" ); document.write( " Answer: \"system%28+u=8%2C+v=5+%29\".
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