document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91670>Question 91670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travels 240 miles on 15 gallons of gas. How far can the car travel on 20 gallons of gas? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66595 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=distance traveled on 20 gal\r<BR>\n" );
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document.write( "One approach is to set up a simple ratio: 15 is to 240 as 20 is to x and this is written as follows:\r<BR>\n" );
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document.write( "15/240=20/x  cross multiply (actually we are multiplying both sides by 240x)\r<BR>\n" );
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document.write( "15x=240*20=4800  divide both sides by 15<BR>\n" );
document.write( "x=320 mi------------------------------------distance travelled on 20 gal\r<BR>\n" );
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document.write( "Another approach would be to determine the mileage the car gets in miles/gal:\r<BR>\n" );
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document.write( "If the car goes 240 mi on 15 gal, then it goes 240/15 or 16 mi on 1 gal.\r<BR>\n" );
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document.write( "Soooooooooo our car gets 16 mi/gal and it can go 16*20  or 320 mi on 20 gal\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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