document.write( "Question 91657: Carl is a years old. His sister Jenny is six more than twice his age. What is the average of their ages? \n" ); document.write( "
Algebra.Com's Answer #66592 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Carl is A years old. \n" ); document.write( ". \n" ); document.write( "His sister is twice his age (2A) plus 6 years. So she is 2A + 6. \n" ); document.write( ". \n" ); document.write( "To average their two ages, add their ages together and divide by 2. Adding their ages results \n" ); document.write( "in: \n" ); document.write( ". \n" ); document.write( "A + 2A + 6 = 3A + 6 \n" ); document.write( ". \n" ); document.write( "Then dividing by 2: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If you would like you can also divide each of the terms in the numerator by 2 and express the \n" ); document.write( "answer as: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little better. \n" ); document.write( " \n" ); document.write( " |