document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91676>Question 91676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kim Lu can now mow 2 lawns in one and a half hours. How long will it take him to mow 6 lawns? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66591 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Kim Lu mows at the rate of 1 lawn every 90min/2 or 45min or (3/4)hr\r<BR>\n" );
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document.write( "Therefore Kim Lu can mow 6 lawns in 6*(3/4)hr or 4.5 hr.\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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