document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1050250>Question 1050250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fish boat can travel 60 km with a 2.5-km/hr current in 2 hr less time than it can travel 60 km against the current. Determine the speed of the fishing boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #665880 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=665880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r be the rate of the boat in still water. Then:<BR>\n" );
document.write( "60/(r+2.5)+2=60/(r-2.5)<BR>\n" );
document.write( "60(r-2.5)+2(rē-6.25)=60(r+2.5)<BR>\n" );
document.write( "60r-150+2rē-12.5=60r+150<BR>\n" );
document.write( "2rē-312.5=0<BR>\n" );
document.write( "4rē-625=0<BR>\n" );
document.write( "(2r+25)(2r-25)=0<BR>\n" );
document.write( "r=12.5, -12.5<BR>\n" );
document.write( "The rate of the boat in still water is 12.5 km/h. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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